0

Primary 6 Algebra Level 1 Ex 5featured

P6-Algebra-L1-Ex 5 Ans: 1–  3 2–  4 3–  2 4–  4 Length of rectangle –>  (z+ 7) cm z + z + 7 + z + z+ 7 = (4z + 14) cm   5–  1 6–  2 4 pencils –>  n cents 20 pencils ->  n¢× 5 = 5n ¢ 5n cents – $1 = (5n – 100) cents

1
0

Primary 5 CA2 Revision 1featured

P5-CA2-Ex 1 Ans: 1–  3 2–  1 3–  2 Area of square –>  8 cm × 10 cm = 80 cm² Base of triangle –>  14 cm – 8 cm = 6 cm Area of triangle –>  1/2 × 6 cm × 10 cm = 30 cm 80 cm + 30 cm = 110 cm²   4–  3 5– Read more

0
0

Primary 4 CA2 Revision 3featured

P4-CA2-Ex 3 Ans: 1–  376 women 11u –>  2068 1u –>  188 188 × 2 = 376 women   2–  $49 Cost of 25 crates of apples –>  $58 × 25 = $1450 Cost of 3 crates of oranges —  $1597 – $1450 = $147 $147 ÷ 3 = $49   3–  $17 Cost of 6.5 kg of prawns –> Read more

0
0

Primary 4 CA2 Revision 1featured

P4-CA2-Ex 1 Ans: 1–  3 2–  4 3–  3 4– 4 5–  2 29/50 + 7/100 = 58/100 + 7/100 = 65/100 = 0.65   6–  3 7–  1 1/3 ≈ 0.333 0.33 = 0.330 0.330 is smaller than 0.333

4
0

Primary 3 August Review 1featured

P3-Aug-Review-1 Ans: 1– 3 2–  4 3– 2 4–  3 5–  3 6–  3 The clock shows 6.20 p.m.. 15 minutes before 6.20 p.m. –>  6.05 p.m.   7–  1 Original length of string ->  2 m 27 cm -> 227 cm 227 cm – 78 cm = 149 cm

2
0

Primary 6 Prelims Revision 9featured

P6-Prelims-Ex 9 Ans: 1– $45 Julian –>  1u Frederick –>  2u Marcus –>  6u 5u –> $25 1u –>  $5 $5 × 9u = $45   2–  16 more tricycles Assume all are tricycles –> 56 × 3 = 168 wheels 168 – 148 = 20 wheels extra Each bicycle has 1 lesser wheel than each tricycle. Therefore, 20 ÷ Read more

0
0

Primary 6 Prelims Revision 8featured

P6-Prelims-Ex 8 Ans: 1–  966 Lowest common multiple of 2, 3 and 7 –>  42 999 ÷ 42 = 23 R 33 23 × 42 = 966   2–  75% 3–  Thousandths 4–  12m – 7 5–  28% 6–  $6000 7–  $2375 8–  94 marks Total marks for the 3 tests –>  79 marks × 3 = 237 237 Read more

0
Loading...